I had a sudden thought. I haven't looked at much just now, but is there really nothing wrong here!? ( there must be. But throwing it out there... because you're so dang picky! )

Heh, you're thinking outside the box now. Well.... you're half right. I'll say that, which isn't enough.

Im in calculus, I would know.

Darn you! I'm only in Geometry! I'm in 9th grade, age 14, honors... whatever...


-2+(3/2)^2=-2+(3/2)^2...
(2-1.5)(2-1.5)=(1-1.5)(1-1.5)...
or rather, (2)^2+(-1.5)^2=(1) STOP
Why the hell is -2 becoming a +1? Right now I'm getting the idea that for the -'s and +'s to be reversed, the whole equation was x'd or /'d by -1, making the +'s -'s and -'s +'s. But 2 should not become 1 magically!?

Getting confused yet?
I could give a hint, but that might give it away.

The only confusion in my life in math is proofing. [please wait for response...]

lol, k... *Waits*

Okay, on paper, I'm seeing something... ignoring the 9/4 crap, I'm seeing
1)
Original:
4-6 = 1-3
(2)^2 = (1)^2
4 = 1...
Thinking around part 1:
4-6 = 1-3
4-6+6 = 1-3+6
4 = (1+3 = 4)
Thinking around part 2:
4-6 = 1-3
for the transition, did we manipulate each side differently? Like, adding 6 to one side and 3 to the other, upsetting the balance? (I'll look at it bass ackwards...
(2-3/2)^2 = (1-3/2)^2 becomes
4-6+9/4 = 1-3+9/4 ... ... ...whoever wrote these steps must've progressed wrong. Duh. That was no help. )
1^2=1, while2^2=4, and it seemed 1=4 in the problem. I do believe I'm seeing the problem here, but I can't pull out the exact location... but it has to do with

we want these things equalled and squared...
2 and 1 are close, 3 doubled is 6, those are the aside values
added together in the 3rd line, where 2^2+(3*2) = 1^2+(3*1)
could this be the connection!? (I wish my math-solving mind could talk in a language other than processing... )

The answer is simpler than you're thinking.

thing is, in order to pinpoint a simple answer at times like these (when you've rejected all my other words), I must go complex to find someone else's satisfaction.

,,,

Hint:
There are 2 answers. How?

No... you ruined it for me... Wait! I'm picking up something (again, imagine that!)...
has something to do with the argument of doubling and squaring, both being done but... at.. different... times!

....
You're thinking about this wrong. I even gave a good hint.

Well, are you sure? My post was a bit odd...
I think there are steps in between what we see that weren't listed.
About the *2 & ^2 happening, imagine like this:
Type A: Double both side. Then square both sides.
Type B (the wrong way): Double one side. "as long as I do it later, it'll still count, right?" Then square both sides. "Okay, now I'll double that other side."
Or maybe it's a squaring-before-doubling issue.
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At the time you learned this, in a day, how many of these did you have to solve and quickly? You're quite literally giving me a headache. (Speaking of which, I better get going on my homework soon...)

You're still wrong...

Final Hint:
2 squared=4
-2 squared=4
Square Root 4=?

OMG, such an idiot, I am... forgetting something so simple... for that,
^2 root of 4 would be whatever fits in here |#| and = +4... in other words, +/-4... but I must ask: does it really get THAT F***IN' RETARDED and MUNDANE at the level of math where you're up at (calculus... what is it anyway!?)? 'Cause that was preposterous if that was the answer. I see no significance at all here. There may as well be no math problem. All this could ever serve as is a brainteaser. And it didn't even tease my brain. It gave me a headache. Because it was pointless. IMMA FIRIN MAH LAZER!!! (it's a new smiley! )
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(also, please don't tell me you wait for e-mail notification of topics in this forum, they always come, like, a half-hour later than when the actual event happens; I open up the subscriptions page and refresh it over and over, all day long...)