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Algebra 1 
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Blue Mage, care to try my unspeakably easy problem?

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Tue Feb 09, 2010 1:20 am
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What a joke, there is a cap on what questions can be asked in order to allow everyone to know the answer

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Tue Feb 09, 2010 2:16 am
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Algebra 1 spans only the basics of Algebra. Just keep it easy so nobody gets bored failing the problems, DVDV.

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Tue Feb 09, 2010 6:22 pm
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So we can't kill it?

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Tue Feb 09, 2010 9:37 pm
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No.

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Tue Feb 09, 2010 9:47 pm
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velosareon wrote:
X=-6
y=8

ok my turn,

y=3x/4+21

-9x+3y=66

How many solutions does this linear equation have?


Is this too hard?

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Tue Feb 09, 2010 11:22 pm
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I already answered that

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Tue Feb 09, 2010 11:31 pm
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I don't see an answer...

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Tue Feb 09, 2010 11:33 pm
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|~DVDV~| wrote:
velosareon wrote:
velosareon wrote:
yup i got it right!

K here it is (it's very easy):

y=3x/4+10
4x+3y=30

How many solutions does this linear equation have?

Try solving this one Blue Mage! (it's really easy)


infinite

Ok, how's this (btw, I don't know what Algebra 1 is but stuff it, go learn algebra 10 (or whatever the highest is) and don't complain)

Simplify
((2x+y)/(x-3)+(x-y)/(x+3)-(3x+2y)/(x^2+x-6))^2=4

then find the relationship between x and y

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Wed Feb 10, 2010 12:57 am
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velosareon wrote:
velosareon wrote:
X=-6
y=8

ok my turn,

y=3x/4+21

-9x+3y=66

How many solutions does this linear equation have?


Is this too hard?


THIS ONE

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Wed Feb 10, 2010 1:00 am
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Blue Mage wrote:
x² is part of Algebra 1. You probably aren't that far, though.

Yeah, we're not there. I just browsed the chapters the other day. All we've learned with exponents is numbers with exponents in equations.

Hmm...
((2x+y)/(x-3)+(x-y)/(x+3)-(3x+2y)/(x^2+x-6))^2=4
(2x+y/x-3+x-y/x+3-3x+2y/x^2+x-6)^2=4
(2x+y/2x-3-y/2x+3+2y/x^2+x-6)^2=4
(2x+y/2x-y/2x+2y/x^2+x)^2=10
(y/-y/2x+2y/x^2+x)^2=10
(-1/2x+2y/x^2+x)^2=10

And I can't figure out what to do from there.

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Wed Feb 10, 2010 8:40 pm
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We decided to drop that one because it's not Algebra 1 so try mine instead!

y=3x/4+21

-9x+3y=66

How many solutions does this linear equation have?

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Wed Feb 10, 2010 9:30 pm
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... easy so ridiclously easy....A. because you have two linear equations right thar and B. Linear equations go in straight neverending graphs so infinite # of solutions if not kill my math teacher I am in 8th grade...

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Wed Feb 10, 2010 10:41 pm
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lol i'm in 8th grade middle school and i'm in algebra 2

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Thu Feb 11, 2010 11:41 pm
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yeah..... different countries have different standards (We officially caall it algrebra 1 but learn SOME not all 2).
Hwever I am sure he meqant what is the solution for the linear equations... if so no prob.


y=3x/4+21
Y=3/4x +21 okay so now we...


-9x+3y=66
-36/4x + 9/4x +63= 66
-27/4x =3
so far -6.75x=3 .4(barnotation) or for simplicity x=9/4 so now that the domain is found we plug it in.(9/4,[blank])
y=3(4/9) +21 12/9 4/3 +21 4/3 + 63/3 okay so now y = 67/3 and now to divide... 22.3 (barnotation) so that be 198/9 divide (gulp I hate long division) j/king 22 so that was no mistake so far and it is (9/4 or .4 [bar notation],22.3[bar notation] or... 22 1/3) so (9/4,22 1/3) or (.4[bar], 22.3[bar]) now to graph to see f I am right... (oh god) oh wait I JUST realized I did the overly complicated and long way... crap take your awnser....

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Fri Feb 12, 2010 12:02 am
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